Base | Representation |
---|---|
bin | 1001000001111101000… |
… | …0000011100101011111 |
3 | 112211110012011100111101 |
4 | 2100133100003211133 |
5 | 10020213120002333 |
6 | 155134411333531 |
7 | 14131406543533 |
oct | 2203720034537 |
9 | 484405140441 |
10 | 155143125343 |
11 | 5a883282368 |
12 | 260991512a7 |
13 | 11825c70aab |
14 | 771a86bbc3 |
15 | 40803a867d |
hex | 241f40395f |
155143125343 has 2 divisors, whose sum is σ = 155143125344. Its totient is φ = 155143125342.
The previous prime is 155143125341. The next prime is 155143125353. The reversal of 155143125343 is 343521341551.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 155143125343 - 21 = 155143125341 is a prime.
Together with 155143125341, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (155143125341) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77571562671 + 77571562672.
It is an arithmetic number, because the mean of its divisors is an integer number (77571562672).
Almost surely, 2155143125343 is an apocalyptic number.
155143125343 is a deficient number, since it is larger than the sum of its proper divisors (1).
155143125343 is an equidigital number, since it uses as much as digits as its factorization.
155143125343 is an evil number, because the sum of its binary digits is even.
The product of its digits is 108000, while the sum is 37.
Adding to 155143125343 its reverse (343521341551), we get a palindrome (498664466894).
The spelling of 155143125343 in words is "one hundred fifty-five billion, one hundred forty-three million, one hundred twenty-five thousand, three hundred forty-three".
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