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1552341551051 is a prime number
BaseRepresentation
bin10110100101101110110…
…001000100011111001011
312111101212100111102112102
4112211232301010133023
5200413143414113201
63145045202504015
7220103320320524
oct26455661043713
95441770442472
101552341551051
115493873773a5
12210a3006500b
13b3501318ca5
14551c2d6384b
152a5a75bc26b
hex1696ec447cb

1552341551051 has 2 divisors, whose sum is σ = 1552341551052. Its totient is φ = 1552341551050.

The previous prime is 1552341551039. The next prime is 1552341551053. The reversal of 1552341551051 is 1501551432551.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1552341551051 - 230 = 1551267809227 is a prime.

It is a super-2 number, since 2×15523415510512 (a number of 25 digits) contains 22 as substring.

Together with 1552341551053, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 1552341550996 and 1552341551014.

It is not a weakly prime, because it can be changed into another prime (1552341551053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 776170775525 + 776170775526.

It is an arithmetic number, because the mean of its divisors is an integer number (776170775526).

Almost surely, 21552341551051 is an apocalyptic number.

1552341551051 is a deficient number, since it is larger than the sum of its proper divisors (1).

1552341551051 is an equidigital number, since it uses as much as digits as its factorization.

1552341551051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 75000, while the sum is 38.

The spelling of 1552341551051 in words is "one trillion, five hundred fifty-two billion, three hundred forty-one million, five hundred fifty-one thousand, fifty-one".