Base | Representation |
---|---|
bin | 1110001000000101010010… |
… | …0010101001101010010011 |
3 | 2000222211212012001022120212 |
4 | 3202001110202221222103 |
5 | 4013434034122041034 |
6 | 53011151142554335 |
7 | 3162102636423305 |
oct | 342012442515223 |
9 | 60884765038525 |
10 | 15532020112019 |
11 | 4a49102486074 |
12 | 18aa2621389ab |
13 | 8888810cc0a8 |
14 | 3b9a7a555975 |
15 | 1be0544082ce |
hex | e20548a9a93 |
15532020112019 has 2 divisors, whose sum is σ = 15532020112020. Its totient is φ = 15532020112018.
The previous prime is 15532020111997. The next prime is 15532020112051. The reversal of 15532020112019 is 91021102023551.
It is an a-pointer prime, because the next prime (15532020112051) can be obtained adding 15532020112019 to its sum of digits (32).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 15532020112019 - 216 = 15532020046483 is a prime.
It is a super-2 number, since 2×155320201120192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (15532020112099) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7766010056009 + 7766010056010.
It is an arithmetic number, because the mean of its divisors is an integer number (7766010056010).
Almost surely, 215532020112019 is an apocalyptic number.
15532020112019 is a deficient number, since it is larger than the sum of its proper divisors (1).
15532020112019 is an equidigital number, since it uses as much as digits as its factorization.
15532020112019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5400, while the sum is 32.
The spelling of 15532020112019 in words is "fifteen trillion, five hundred thirty-two billion, twenty million, one hundred twelve thousand, nineteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •