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155345050247 is a prime number
BaseRepresentation
bin1001000010101101001…
…0010101101010000111
3112211222021010012101112
42100223102111222013
510021121313101442
6155210423315235
714136411066062
oct2205322255207
9484867105345
10155345050247
115a97725a552
12261348abb1b
1311858a5029a
1477395d18d9
154092e93082
hex242b495a87

155345050247 has 2 divisors, whose sum is σ = 155345050248. Its totient is φ = 155345050246.

The previous prime is 155345050123. The next prime is 155345050249. The reversal of 155345050247 is 742050543551.

It is a strong prime.

It is an emirp because it is prime and its reverse (742050543551) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 155345050247 - 236 = 86625573511 is a prime.

It is a super-2 number, since 2×1553450502472 (a number of 23 digits) contains 22 as substring.

Together with 155345050249, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (155345050249) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77672525123 + 77672525124.

It is an arithmetic number, because the mean of its divisors is an integer number (77672525124).

Almost surely, 2155345050247 is an apocalyptic number.

155345050247 is a deficient number, since it is larger than the sum of its proper divisors (1).

155345050247 is an equidigital number, since it uses as much as digits as its factorization.

155345050247 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 420000, while the sum is 41.

Adding to 155345050247 its reverse (742050543551), we get a palindrome (897395593798).

The spelling of 155345050247 in words is "one hundred fifty-five billion, three hundred forty-five million, fifty thousand, two hundred forty-seven".