Base | Representation |
---|---|
bin | 11100111101101101… |
… | …11110100011101111 |
3 | 1111010201021122021022 |
4 | 32132312332203233 |
5 | 223321312122111 |
6 | 11051004524355 |
7 | 1060226534264 |
oct | 163666764357 |
9 | 44121248238 |
10 | 15550114031 |
11 | 665a6a7911 |
12 | 301b8506bb |
13 | 160a7c940a |
14 | a7730326b |
15 | 61027b2db |
hex | 39edbe8ef |
15550114031 has 2 divisors, whose sum is σ = 15550114032. Its totient is φ = 15550114030.
The previous prime is 15550113973. The next prime is 15550114057. The reversal of 15550114031 is 13041105551.
It is an a-pointer prime, because the next prime (15550114057) can be obtained adding 15550114031 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-15550114031 is a prime.
It is a super-2 number, since 2×155501140312 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (15550117031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7775057015 + 7775057016.
It is an arithmetic number, because the mean of its divisors is an integer number (7775057016).
Almost surely, 215550114031 is an apocalyptic number.
15550114031 is a deficient number, since it is larger than the sum of its proper divisors (1).
15550114031 is an equidigital number, since it uses as much as digits as its factorization.
15550114031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1500, while the sum is 26.
Adding to 15550114031 its reverse (13041105551), we get a palindrome (28591219582).
The spelling of 15550114031 in words is "fifteen billion, five hundred fifty million, one hundred fourteen thousand, thirty-one".
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