Base | Representation |
---|---|
bin | 1001000011010010110… |
… | …1110000010010010011 |
3 | 112212101021202200011102 |
4 | 2100310231300102103 |
5 | 10021432311412042 |
6 | 155234233535015 |
7 | 14143341443564 |
oct | 2206455602223 |
9 | 485337680142 |
10 | 155503232147 |
11 | 5aa4857a99a |
12 | 2617987446b |
13 | 11882755343 |
14 | 775260a16b |
15 | 40a1cdbb32 |
hex | 2434b70493 |
155503232147 has 2 divisors, whose sum is σ = 155503232148. Its totient is φ = 155503232146.
The previous prime is 155503232089. The next prime is 155503232161. The reversal of 155503232147 is 741232305551.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 155503232147 - 222 = 155499037843 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 155503232147.
It is not a weakly prime, because it can be changed into another prime (155503234147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77751616073 + 77751616074.
It is an arithmetic number, because the mean of its divisors is an integer number (77751616074).
Almost surely, 2155503232147 is an apocalyptic number.
155503232147 is a deficient number, since it is larger than the sum of its proper divisors (1).
155503232147 is an equidigital number, since it uses as much as digits as its factorization.
155503232147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 126000, while the sum is 38.
Adding to 155503232147 its reverse (741232305551), we get a palindrome (896735537698).
The spelling of 155503232147 in words is "one hundred fifty-five billion, five hundred three million, two hundred thirty-two thousand, one hundred forty-seven".
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