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1564513269713 is a prime number
BaseRepresentation
bin10110110001000100010…
…000011111011111010001
312112120021121201210121022
4112301010100133133101
5201113110344112323
63154421045005225
7221014045242002
oct26610420373721
95476247653538
101564513269713
11553562a54819
122132683b3815
13b46c0c15194
1455a196c11a9
152aa6ae5c4c8
hex16c4441f7d1

1564513269713 has 2 divisors, whose sum is σ = 1564513269714. Its totient is φ = 1564513269712.

The previous prime is 1564513269667. The next prime is 1564513269727. The reversal of 1564513269713 is 3179623154651.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 963365806144 + 601147463569 = 981512^2 + 775337^2 .

It is an emirp because it is prime and its reverse (3179623154651) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1564513269713 - 218 = 1564513007569 is a prime.

It is a super-2 number, since 2×15645132697132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1564513269773) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 782256634856 + 782256634857.

It is an arithmetic number, because the mean of its divisors is an integer number (782256634857).

Almost surely, 21564513269713 is an apocalyptic number.

It is an amenable number.

1564513269713 is a deficient number, since it is larger than the sum of its proper divisors (1).

1564513269713 is an equidigital number, since it uses as much as digits as its factorization.

1564513269713 is an evil number, because the sum of its binary digits is even.

The product of its digits is 4082400, while the sum is 53.

The spelling of 1564513269713 in words is "one trillion, five hundred sixty-four billion, five hundred thirteen million, two hundred sixty-nine thousand, seven hundred thirteen".