16020171262547 has 2 divisors, whose sum is σ = 16020171262548. Its totient is φ = 16020171262546.

The previous prime is 16020171262541. The next prime is 16020171262549. The reversal of 16020171262547 is 74526217102061.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-16020171262547 is a prime.

Together with 16020171262549, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 16020171262498 and 16020171262507.

It is not a weakly prime, because it can be changed into another prime (16020171262541) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8010085631273 + 8010085631274.

It is an arithmetic number, because the mean of its divisors is an integer number (8010085631274).

Almost surely, 2^{16020171262547} is an apocalyptic number.

16020171262547 is a deficient number, since it is larger than the sum of its proper divisors (1).

16020171262547 is an equidigital number, since it uses as much as digits as its factorization.

16020171262547 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 282240, while the sum is 44.

The spelling of 16020171262547 in words is "sixteen trillion, twenty billion, one hundred seventy-one million, two hundred sixty-two thousand, five hundred forty-seven".