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160257253121237 is a prime number
BaseRepresentation
bin100100011100000011001100…
…101001010001110011010101
3210000102102222111211122020002
4210130003030221101303111
5132001123323244334422
61324501055444221045
745520130061551546
oct4434031451216325
9700372874748202
10160257253121237
11470767a05418a8
1215b82b1999a785
136b5626a65251c
142b806c73664cd
15137d9d3d04692
hex91c0cca51cd5

160257253121237 has 2 divisors, whose sum is σ = 160257253121238. Its totient is φ = 160257253121236.

The previous prime is 160257253121183. The next prime is 160257253121257. The reversal of 160257253121237 is 732121352752061.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151090461436996 + 9166791684241 = 12291886^2 + 3027671^2 .

It is a cyclic number.

It is not a de Polignac number, because 160257253121237 - 238 = 159982375214293 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 160257253121191 and 160257253121200.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (160257253121257) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80128626560618 + 80128626560619.

It is an arithmetic number, because the mean of its divisors is an integer number (80128626560619).

Almost surely, 2160257253121237 is an apocalyptic number.

It is an amenable number.

160257253121237 is a deficient number, since it is larger than the sum of its proper divisors (1).

160257253121237 is an equidigital number, since it uses as much as digits as its factorization.

160257253121237 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1058400, while the sum is 47.

The spelling of 160257253121237 in words is "one hundred sixty trillion, two hundred fifty-seven billion, two hundred fifty-three million, one hundred twenty-one thousand, two hundred thirty-seven".