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16030534133 is a prime number
BaseRepresentation
bin11101110110111111…
…01000100111110101
31112101012021111202102
432323133220213311
5230312304043013
611210405551445
71105152202055
oct167337504765
945335244672
1016030534133
116886900619
123134715585
1316861b7373
14ac103d565
1563c527d58
hex3bb7e89f5

16030534133 has 2 divisors, whose sum is σ = 16030534134. Its totient is φ = 16030534132.

The previous prime is 16030534127. The next prime is 16030534139. The reversal of 16030534133 is 33143503061.

It is a balanced prime because it is at equal distance from previous prime (16030534127) and next prime (16030534139).

It can be written as a sum of positive squares in only one way, i.e., 12342765604 + 3687768529 = 111098^2 + 60727^2 .

It is a cyclic number.

It is not a de Polignac number, because 16030534133 - 212 = 16030530037 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 16030534096 and 16030534105.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16030534139) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8015267066 + 8015267067.

It is an arithmetic number, because the mean of its divisors is an integer number (8015267067).

Almost surely, 216030534133 is an apocalyptic number.

It is an amenable number.

16030534133 is a deficient number, since it is larger than the sum of its proper divisors (1).

16030534133 is an equidigital number, since it uses as much as digits as its factorization.

16030534133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9720, while the sum is 29.

The spelling of 16030534133 in words is "sixteen billion, thirty million, five hundred thirty-four thousand, one hundred thirty-three".