Base | Representation |
---|---|
bin | 1110100101010011110011… |
… | …1000010100001001100111 |
3 | 2002202211220101111111022212 |
4 | 3221110330320110021213 |
5 | 4100200401340432102 |
6 | 54033551332514035 |
7 | 3243266536616633 |
oct | 351247470241147 |
9 | 62684811444285 |
10 | 16034134311527 |
11 | 512204689a992 |
12 | 196b63317b91b |
13 | 8c4021269b97 |
14 | 3d60b047ddc3 |
15 | 1cc14095ac52 |
hex | e953ce14267 |
16034134311527 has 2 divisors, whose sum is σ = 16034134311528. Its totient is φ = 16034134311526.
The previous prime is 16034134311487. The next prime is 16034134311623. The reversal of 16034134311527 is 72511343143061.
16034134311527 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16034134311527 - 26 = 16034134311463 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16034134311827) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8017067155763 + 8017067155764.
It is an arithmetic number, because the mean of its divisors is an integer number (8017067155764).
Almost surely, 216034134311527 is an apocalyptic number.
16034134311527 is a deficient number, since it is larger than the sum of its proper divisors (1).
16034134311527 is an equidigital number, since it uses as much as digits as its factorization.
16034134311527 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 181440, while the sum is 41.
Adding to 16034134311527 its reverse (72511343143061), we get a palindrome (88545477454588).
The spelling of 16034134311527 in words is "sixteen trillion, thirty-four billion, one hundred thirty-four million, three hundred eleven thousand, five hundred twenty-seven".
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