Base | Representation |
---|---|
bin | 1110100101010011110011… |
… | …1000010100001011000111 |
3 | 2002202211220101111111110102 |
4 | 3221110330320110023013 |
5 | 4100200401340432443 |
6 | 54033551332514315 |
7 | 3243266536620131 |
oct | 351247470241307 |
9 | 62684811444412 |
10 | 16034134311623 |
11 | 512204689aa6a |
12 | 196b63317b99b |
13 | 8c4021269c3c |
14 | 3d60b0480051 |
15 | 1cc14095acb8 |
hex | e953ce142c7 |
16034134311623 has 2 divisors, whose sum is σ = 16034134311624. Its totient is φ = 16034134311622.
The previous prime is 16034134311527. The next prime is 16034134311631. The reversal of 16034134311623 is 32611343143061.
16034134311623 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16034134311623 - 222 = 16034130117319 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16034134311653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8017067155811 + 8017067155812.
It is an arithmetic number, because the mean of its divisors is an integer number (8017067155812).
Almost surely, 216034134311623 is an apocalyptic number.
16034134311623 is a deficient number, since it is larger than the sum of its proper divisors (1).
16034134311623 is an equidigital number, since it uses as much as digits as its factorization.
16034134311623 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 93312, while the sum is 38.
Adding to 16034134311623 its reverse (32611343143061), we get a palindrome (48645477454684).
The spelling of 16034134311623 in words is "sixteen trillion, thirty-four billion, one hundred thirty-four million, three hundred eleven thousand, six hundred twenty-three".
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