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160399055750119 is a prime number
BaseRepresentation
bin100100011110000111010000…
…101111011000001111100111
3210000220222222222111112220221
4210132013100233120033213
5132010434231233000434
61325050150422505211
745533310062164624
oct4436072057301747
9700828888445827
10160399055750119
114712094841577a
1215ba64b3295207
136b66748815014
142b874da15334b
151382532ded2b4
hex91e1d0bd83e7

160399055750119 has 2 divisors, whose sum is σ = 160399055750120. Its totient is φ = 160399055750118.

The previous prime is 160399055750117. The next prime is 160399055750149. The reversal of 160399055750119 is 911057550993061.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 160399055750119 - 21 = 160399055750117 is a prime.

It is a super-4 number, since 4×1603990557501194 (a number of 58 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

Together with 160399055750117, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (160399055750117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80199527875059 + 80199527875060.

It is an arithmetic number, because the mean of its divisors is an integer number (80199527875060).

Almost surely, 2160399055750119 is an apocalyptic number.

160399055750119 is a deficient number, since it is larger than the sum of its proper divisors (1).

160399055750119 is an equidigital number, since it uses as much as digits as its factorization.

160399055750119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11481750, while the sum is 61.

The spelling of 160399055750119 in words is "one hundred sixty trillion, three hundred ninety-nine billion, fifty-five million, seven hundred fifty thousand, one hundred nineteen".