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16106705315837 is a prime number
BaseRepresentation
bin1110101001100010001001…
…1100101110011111111101
32010000210012222122111002022
43222120202130232133331
54102343013030101322
654131152425205525
73251446113153653
oct352304234563775
963023188574068
1016106705315837
11514a8a7282604
1219817070308a5
138cab18244656
143d97d670add3
151cde8bb20942
hexea62272e7fd

16106705315837 has 2 divisors, whose sum is σ = 16106705315838. Its totient is φ = 16106705315836.

The previous prime is 16106705315717. The next prime is 16106705315873. The reversal of 16106705315837 is 73851350760161.

Together with next prime (16106705315873) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9738824662681 + 6367880653156 = 3120709^2 + 2523466^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16106705315837 is a prime.

It is a super-2 number, since 2×161067053158372 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16106705314837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8053352657918 + 8053352657919.

It is an arithmetic number, because the mean of its divisors is an integer number (8053352657919).

Almost surely, 216106705315837 is an apocalyptic number.

It is an amenable number.

16106705315837 is a deficient number, since it is larger than the sum of its proper divisors (1).

16106705315837 is an equidigital number, since it uses as much as digits as its factorization.

16106705315837 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3175200, while the sum is 53.

The spelling of 16106705315837 in words is "sixteen trillion, one hundred six billion, seven hundred five million, three hundred fifteen thousand, eight hundred thirty-seven".