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161161551110117 is a prime number
BaseRepresentation
bin100100101001001101011001…
…000000010101111111100101
3210010121220010121001011210202
4210221031121000111333211
5132110432324041010432
61330432332224400245
745642352321621115
oct4451153100257745
9703556117034722
10161161551110117
1147395259146318
12160aa231476085
136bc06136a55cc
142bb23914b1045
1513972ad819462
hex929359015fe5

161161551110117 has 2 divisors, whose sum is σ = 161161551110118. Its totient is φ = 161161551110116.

The previous prime is 161161551110071. The next prime is 161161551110123. The reversal of 161161551110117 is 711011155161161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 85972691445316 + 75188859664801 = 9272146^2 + 8671151^2 .

It is a cyclic number.

It is not a de Polignac number, because 161161551110117 - 222 = 161161546915813 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (161161551110137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80580775555058 + 80580775555059.

It is an arithmetic number, because the mean of its divisors is an integer number (80580775555059).

Almost surely, 2161161551110117 is an apocalyptic number.

It is an amenable number.

161161551110117 is a deficient number, since it is larger than the sum of its proper divisors (1).

161161551110117 is an equidigital number, since it uses as much as digits as its factorization.

161161551110117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6300, while the sum is 38.

The spelling of 161161551110117 in words is "one hundred sixty-one trillion, one hundred sixty-one billion, five hundred fifty-one million, one hundred ten thousand, one hundred seventeen".