Base | Representation |
---|---|
bin | 1110101010100011101111… |
… | …1110101000011001100110 |
3 | 2010002110200010120002101210 |
4 | 3222220323332220121212 |
5 | 4103140043224101314 |
6 | 54143223553532250 |
7 | 3252641343244401 |
oct | 352507376503146 |
9 | 63073603502353 |
10 | 16124313503334 |
11 | 5157312681483 |
12 | 1984bbbb74086 |
13 | 8cc69323c1ca |
14 | 3da5c70a4d38 |
15 | 1ce66c8d1559 |
hex | eaa3bfa8666 |
16124313503334 has 32 divisors (see below), whose sum is σ = 32440602060000. Its totient is φ = 5342864328704.
The previous prime is 16124313503329. The next prime is 16124313503357. The reversal of 16124313503334 is 43330531342161.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 16124313503292 and 16124313503301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10400349 + ... + 11849720.
It is an arithmetic number, because the mean of its divisors is an integer number (1013768814375).
Almost surely, 216124313503334 is an apocalyptic number.
16124313503334 is an abundant number, since it is smaller than the sum of its proper divisors (16316288556666).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
16124313503334 is a wasteful number, since it uses less digits than its factorization.
16124313503334 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22250792.
The product of its (nonzero) digits is 233280, while the sum is 39.
Adding to 16124313503334 its reverse (43330531342161), we get a palindrome (59454844845495).
The spelling of 16124313503334 in words is "sixteen trillion, one hundred twenty-four billion, three hundred thirteen million, five hundred three thousand, three hundred thirty-four".
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