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16125021331 is a prime number
BaseRepresentation
bin11110000010010000…
…00100110010010011
31112121210001221211021
433001020010302103
5231011001140311
611224023100311
71110410263666
oct170110046223
945553057737
1016125021331
116925177211
1231602a1697
13169c94a853
14acd7d76dd
1564598e171
hex3c1204c93

16125021331 has 2 divisors, whose sum is σ = 16125021332. Its totient is φ = 16125021330.

The previous prime is 16125021317. The next prime is 16125021359. The reversal of 16125021331 is 13312052161.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 16125021331 - 25 = 16125021299 is a prime.

It is a super-2 number, since 2×161250213312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 16125021296 and 16125021305.

It is not a weakly prime, because it can be changed into another prime (16125021391) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8062510665 + 8062510666.

It is an arithmetic number, because the mean of its divisors is an integer number (8062510666).

Almost surely, 216125021331 is an apocalyptic number.

16125021331 is a deficient number, since it is larger than the sum of its proper divisors (1).

16125021331 is an equidigital number, since it uses as much as digits as its factorization.

16125021331 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 16125021331 its reverse (13312052161), we get a palindrome (29437073492).

The spelling of 16125021331 in words is "sixteen billion, one hundred twenty-five million, twenty-one thousand, three hundred thirty-one".