16125140231 has 2 divisors, whose sum is σ = 16125140232. Its totient is φ = 16125140230.

The previous prime is 16125140201. The next prime is 16125140233. The reversal of 16125140231 is 13204152161.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16125140231 - 2⁶ = 16125140167 is a prime.

It is a super-2 number, since 2×16125140231² (a number of 21 digits) contains 22 as substring.

Together with 16125140233, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 16125140231.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16125140233) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8062570115 + 8062570116.

It is an arithmetic number, because the mean of its divisors is an integer number (8062570116).

Almost surely, 2^16125140231 is an apocalyptic number.

16125140231 is a deficient number, since it is larger than the sum of its proper divisors (1).

16125140231 is an equidigital number, since it uses as much as digits as its factorization.

16125140231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 16125140231 its reverse (13204152161), we get a palindrome (29329292392).

The spelling of 16125140231 in words is "sixteen billion, one hundred twenty-five million, one hundred forty thousand, two hundred thirty-one".