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161410929039413 is a prime number
BaseRepresentation
bin100100101100110101101001…
…000101101001100000110101
3210011111201211011121120100022
4210230311221011221200311
5132124024040313230123
61331143053535054525
745666361202216504
oct4454655105514065
9704451734546308
10161410929039413
1147480a99517649
121612a629671445
136c0aca690bb11
142bc048b43283b
15139da06c061c8
hex92cd69169835

161410929039413 has 2 divisors, whose sum is σ = 161410929039414. Its totient is φ = 161410929039412.

The previous prime is 161410929039361. The next prime is 161410929039457. The reversal of 161410929039413 is 314930929014161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 138650224650289 + 22760704389124 = 11774983^2 + 4770818^2 .

It is a cyclic number.

It is not a de Polignac number, because 161410929039413 - 222 = 161410924845109 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (161410929032413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80705464519706 + 80705464519707.

It is an arithmetic number, because the mean of its divisors is an integer number (80705464519707).

Almost surely, 2161410929039413 is an apocalyptic number.

It is an amenable number.

161410929039413 is a deficient number, since it is larger than the sum of its proper divisors (1).

161410929039413 is an equidigital number, since it uses as much as digits as its factorization.

161410929039413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1259712, while the sum is 53.

The spelling of 161410929039413 in words is "one hundred sixty-one trillion, four hundred ten billion, nine hundred twenty-nine million, thirty-nine thousand, four hundred thirteen".