Base | Representation |
---|---|
bin | 100100101100110110001000… |
… | …011101101110110110000111 |
3 | 210011111210011212010210222122 |
4 | 210230312020131232312013 |
5 | 132124031130043241112 |
6 | 1331143222101520155 |
7 | 45666410223465665 |
oct | 4454661035566607 |
9 | 704453155123878 |
10 | 161411455446407 |
11 | 4748123967aa51 |
12 | 1612a755a1305b |
13 | 6c0b05b9ab64a |
14 | 2bc04db2ddc35 |
15 | 139da38038872 |
hex | 92cd8876ed87 |
161411455446407 has 2 divisors, whose sum is σ = 161411455446408. Its totient is φ = 161411455446406.
The previous prime is 161411455446337. The next prime is 161411455446413. The reversal of 161411455446407 is 704644554114161.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 161411455446407 - 226 = 161411388337543 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (161411455446427) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80705727723203 + 80705727723204.
It is an arithmetic number, because the mean of its divisors is an integer number (80705727723204).
Almost surely, 2161411455446407 is an apocalyptic number.
161411455446407 is a deficient number, since it is larger than the sum of its proper divisors (1).
161411455446407 is an equidigital number, since it uses as much as digits as its factorization.
161411455446407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 6451200, while the sum is 53.
The spelling of 161411455446407 in words is "one hundred sixty-one trillion, four hundred eleven billion, four hundred fifty-five million, four hundred forty-six thousand, four hundred seven".
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