Base | Representation |
---|---|
bin | 1001011001010100011… |
… | …1000100110101111111 |
3 | 120102122022122110100101 |
4 | 2112111013010311333 |
5 | 10121034323344413 |
6 | 202053033141531 |
7 | 14443011454354 |
oct | 2262507046577 |
9 | 512568573311 |
10 | 161415449983 |
11 | 625018a4737 |
12 | 2734985a8a7 |
13 | 122b55977a8 |
14 | 7b538c862b |
15 | 42ead84edd |
hex | 25951c4d7f |
161415449983 has 2 divisors, whose sum is σ = 161415449984. Its totient is φ = 161415449982.
The previous prime is 161415449947. The next prime is 161415450011. The reversal of 161415449983 is 389944514161.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 161415449983 - 225 = 161381895551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (161415449933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80707724991 + 80707724992.
It is an arithmetic number, because the mean of its divisors is an integer number (80707724992).
Almost surely, 2161415449983 is an apocalyptic number.
161415449983 is a deficient number, since it is larger than the sum of its proper divisors (1).
161415449983 is an equidigital number, since it uses as much as digits as its factorization.
161415449983 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3732480, while the sum is 55.
The spelling of 161415449983 in words is "one hundred sixty-one billion, four hundred fifteen million, four hundred forty-nine thousand, nine hundred eighty-three".
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