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161415450011 is a prime number
BaseRepresentation
bin1001011001010100011…
…1000100110110011011
3120102122022122110101102
42112111013010312123
510121034323400021
6202053033142015
714443011454424
oct2262507046633
9512568573342
10161415450011
11625018a4762
122734985a90b
13122b55977ca
147b538c864b
1542ead8500b
hex25951c4d9b

161415450011 has 2 divisors, whose sum is σ = 161415450012. Its totient is φ = 161415450010.

The previous prime is 161415449983. The next prime is 161415450013. The reversal of 161415450011 is 110054514161.

161415450011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (110054514161) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 161415450011 - 26 = 161415449947 is a prime.

Together with 161415450013, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (161415450013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80707725005 + 80707725006.

It is an arithmetic number, because the mean of its divisors is an integer number (80707725006).

Almost surely, 2161415450011 is an apocalyptic number.

161415450011 is a deficient number, since it is larger than the sum of its proper divisors (1).

161415450011 is an equidigital number, since it uses as much as digits as its factorization.

161415450011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2400, while the sum is 29.

Adding to 161415450011 its reverse (110054514161), we get a palindrome (271469964172).

The spelling of 161415450011 in words is "one hundred sixty-one billion, four hundred fifteen million, four hundred fifty thousand, eleven".