Base | Representation |
---|---|
bin | 1001011001011100010… |
… | …0011010011100101111 |
3 | 120102201121110201222122 |
4 | 2112113010122130233 |
5 | 10121121231301404 |
6 | 202100205303155 |
7 | 14443560651035 |
oct | 2262704323457 |
9 | 512647421878 |
10 | 161448306479 |
11 | 625193a6269 |
12 | 27358864abb |
13 | 122bc32c9c5 |
14 | 7b57ddc555 |
15 | 42edbc53be |
hex | 259711a72f |
161448306479 has 2 divisors, whose sum is σ = 161448306480. Its totient is φ = 161448306478.
The previous prime is 161448306419. The next prime is 161448306499. The reversal of 161448306479 is 974603844161.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 161448306479 - 28 = 161448306223 is a prime.
It is a super-2 number, since 2×1614483064792 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 161448306479.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (161448306419) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80724153239 + 80724153240.
It is an arithmetic number, because the mean of its divisors is an integer number (80724153240).
Almost surely, 2161448306479 is an apocalyptic number.
161448306479 is a deficient number, since it is larger than the sum of its proper divisors (1).
161448306479 is an equidigital number, since it uses as much as digits as its factorization.
161448306479 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3483648, while the sum is 53.
The spelling of 161448306479 in words is "one hundred sixty-one billion, four hundred forty-eight million, three hundred six thousand, four hundred seventy-nine".
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