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16214041231 is a prime number
BaseRepresentation
bin11110001100110111…
…01010001010001111
31112211222120122011121
433012123222022033
5231201243304411
611240523101411
71112541035143
oct170633521217
945758518147
1016214041231
116970449183
123186071867
1316b521864b
14adb56b223
1564d6c5571
hex3c66ea28f

16214041231 has 2 divisors, whose sum is σ = 16214041232. Its totient is φ = 16214041230.

The previous prime is 16214041223. The next prime is 16214041237. The reversal of 16214041231 is 13214041261.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16214041231 - 23 = 16214041223 is a prime.

It is a super-2 number, since 2×162140412312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 16214041196 and 16214041205.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16214041237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8107020615 + 8107020616.

It is an arithmetic number, because the mean of its divisors is an integer number (8107020616).

Almost surely, 216214041231 is an apocalyptic number.

16214041231 is a deficient number, since it is larger than the sum of its proper divisors (1).

16214041231 is an equidigital number, since it uses as much as digits as its factorization.

16214041231 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 16214041231 its reverse (13214041261), we get a palindrome (29428082492).

The spelling of 16214041231 in words is "sixteen billion, two hundred fourteen million, forty-one thousand, two hundred thirty-one".