16233114341201 has 2 divisors, whose sum is σ = 16233114341202. Its totient is φ = 16233114341200.

The previous prime is 16233114341159. The next prime is 16233114341243. The reversal of 16233114341201 is 10214341133261.

It is a balanced prime because it is at equal distance from previous prime (16233114341159) and next prime (16233114341243).

It can be written as a sum of positive squares in only one way, i.e., 15559861270801 + 673253070400 = 3944599^2 + 820520^2 .

It is an emirp because it is prime and its reverse (10214341133261) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-16233114341201 is a prime.

It is a super-2 number, since 2×16233114341201² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (16233114341251) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8116557170600 + 8116557170601.

It is an arithmetic number, because the mean of its divisors is an integer number (8116557170601).

Almost surely, 2^{16233114341201} is an apocalyptic number.

It is an amenable number.

16233114341201 is a deficient number, since it is larger than the sum of its proper divisors (1).

16233114341201 is an equidigital number, since it uses as much as digits as its factorization.

16233114341201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10368, while the sum is 32.

Adding to 16233114341201 its reverse (10214341133261), we get a palindrome (26447455474462).

The spelling of 16233114341201 in words is "sixteen trillion, two hundred thirty-three billion, one hundred fourteen million, three hundred forty-one thousand, two hundred one".