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162373134100127 is a prime number
BaseRepresentation
bin100100111010110101110000…
…111110101010011010011111
3210021220201102220012010222012
4210322311300332222122133
5132240310134312201002
61333201104340541435
746126033426252256
oct4472656076523237
9707821386163865
10162373134100127
1147812072160225
12162650020b187b
136c7a94a909052
142c14c8a0a579d
1513b8a70351d52
hex93ad70faa69f

162373134100127 has 2 divisors, whose sum is σ = 162373134100128. Its totient is φ = 162373134100126.

The previous prime is 162373134100117. The next prime is 162373134100129. The reversal of 162373134100127 is 721001431373261.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 162373134100127 - 228 = 162372865664671 is a prime.

It is a super-2 number, since 2×1623731341001272 (a number of 29 digits) contains 22 as substring.

Together with 162373134100129, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (162373134100129) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81186567050063 + 81186567050064.

It is an arithmetic number, because the mean of its divisors is an integer number (81186567050064).

Almost surely, 2162373134100127 is an apocalyptic number.

162373134100127 is a deficient number, since it is larger than the sum of its proper divisors (1).

162373134100127 is an equidigital number, since it uses as much as digits as its factorization.

162373134100127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 127008, while the sum is 41.

Adding to 162373134100127 its reverse (721001431373261), we get a palindrome (883374565473388).

The spelling of 162373134100127 in words is "one hundred sixty-two trillion, three hundred seventy-three billion, one hundred thirty-four million, one hundred thousand, one hundred twenty-seven".