Base | Representation |
---|---|
bin | 100101000100100111100111… |
… | …001001011110100001001010 |
3 | 210101021221222112221100002210 |
4 | 211010213213021132201022 |
5 | 132332312412133412100 |
6 | 1334433522134205550 |
7 | 46225423232266335 |
oct | 4504474711364112 |
9 | 711257875840083 |
10 | 163045131544650 |
11 | 47a510631a7493 |
12 | 163532a47b38b6 |
13 | 6cc9122772024 |
14 | 2c395d835361c |
15 | 13cb2a0d3ac50 |
hex | 9449e725e84a |
163045131544650 has 48 divisors (see below), whose sum is σ = 404405720689824. Its totient is φ = 43472917394880.
The previous prime is 163045131544571. The next prime is 163045131544693. The reversal of 163045131544650 is 56445131540361.
It is a self number, because there is not a number n which added to its sum of digits gives 163045131544650.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 71173072 + ... + 73428171.
It is an arithmetic number, because the mean of its divisors is an integer number (8425119181038).
Almost surely, 2163045131544650 is an apocalyptic number.
163045131544650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
163045131544650 is an abundant number, since it is smaller than the sum of its proper divisors (241360589145174).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
163045131544650 is a wasteful number, since it uses less digits than its factorization.
163045131544650 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 144608775 (or 144608770 counting only the distinct ones).
The product of its (nonzero) digits is 2592000, while the sum is 48.
The spelling of 163045131544650 in words is "one hundred sixty-three trillion, forty-five billion, one hundred thirty-one million, five hundred forty-four thousand, six hundred fifty".
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