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163054534702133 is a prime number
BaseRepresentation
bin100101000100110000010111…
…100111101011010000110101
3210101022212020212122020012202
4211010300113213223100311
5132332441141340432013
61334442115200354245
746226205241642544
oct4504602747532065
9711285225566182
10163054534702133
1147a5504901a918
1216355089915985
136cc9c908cab39
142c39c4b11215b
1513cb651601858
hex944c179eb435

163054534702133 has 2 divisors, whose sum is σ = 163054534702134. Its totient is φ = 163054534702132.

The previous prime is 163054534702127. The next prime is 163054534702159. The reversal of 163054534702133 is 331207435450361.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 134502632515729 + 28551902186404 = 11597527^2 + 5343398^2 .

It is a cyclic number.

It is not a de Polignac number, because 163054534702133 - 222 = 163054530507829 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (163054534702123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81527267351066 + 81527267351067.

It is an arithmetic number, because the mean of its divisors is an integer number (81527267351067).

Almost surely, 2163054534702133 is an apocalyptic number.

It is an amenable number.

163054534702133 is a deficient number, since it is larger than the sum of its proper divisors (1).

163054534702133 is an equidigital number, since it uses as much as digits as its factorization.

163054534702133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2721600, while the sum is 47.

The spelling of 163054534702133 in words is "one hundred sixty-three trillion, fifty-four billion, five hundred thirty-four million, seven hundred two thousand, one hundred thirty-three".