Base | Representation |
---|---|
bin | 1110110110010000111111… |
… | …0101010000111000001100 |
3 | 2010210200210201121102100002 |
4 | 3231210033311100320030 |
5 | 4114433443144004400 |
6 | 54415445113423432 |
7 | 3303321350025305 |
oct | 355441765207014 |
9 | 63720721542302 |
10 | 16325436313100 |
11 | 5224640217232 |
12 | 19b7b8b70ab78 |
13 | 915636067355 |
14 | 4062263417ac |
15 | 1d49de6e4ed5 |
hex | ed90fd50e0c |
16325436313100 has 36 divisors (see below), whose sum is σ = 35433443963400. Its totient is φ = 6528838642560.
The previous prime is 16325436313093. The next prime is 16325436313111. The reversal of 16325436313100 is 131363452361.
16325436313100 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×163254363131002 (a number of 27 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 16207190 + ... + 17184989.
Almost surely, 216325436313100 is an apocalyptic number.
16325436313100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
16325436313100 is an abundant number, since it is smaller than the sum of its proper divisors (19108007650300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
16325436313100 is a wasteful number, since it uses less digits than its factorization.
16325436313100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33397082 (or 33397075 counting only the distinct ones).
The product of its (nonzero) digits is 116640, while the sum is 38.
Adding to 16325436313100 its reverse (131363452361), we get a palindrome (16456799765461).
The spelling of 16325436313100 in words is "sixteen trillion, three hundred twenty-five billion, four hundred thirty-six million, three hundred thirteen thousand, one hundred".
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