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16335466421 is a prime number
BaseRepresentation
bin11110011011010101…
…10110111110110101
31120011110001200012212
433031222312332311
5231423334411141
611300541423205
71115544113351
oct171552667665
946143050185
1016335466421
116a22a4377a
1231ba86ab05
131704421181
14b0d738461
156591ad2eb
hex3cdab6fb5

16335466421 has 2 divisors, whose sum is σ = 16335466422. Its totient is φ = 16335466420.

The previous prime is 16335466417. The next prime is 16335466423. The reversal of 16335466421 is 12466453361.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14444434225 + 1891032196 = 120185^2 + 43486^2 .

It is an emirp because it is prime and its reverse (12466453361) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 16335466421 - 22 = 16335466417 is a prime.

It is a super-3 number, since 3×163354664213 (a number of 32 digits) contains 333 as substring.

Together with 16335466423, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16335466423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8167733210 + 8167733211.

It is an arithmetic number, because the mean of its divisors is an integer number (8167733211).

Almost surely, 216335466421 is an apocalyptic number.

It is an amenable number.

16335466421 is a deficient number, since it is larger than the sum of its proper divisors (1).

16335466421 is an equidigital number, since it uses as much as digits as its factorization.

16335466421 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 311040, while the sum is 41.

The spelling of 16335466421 in words is "sixteen billion, three hundred thirty-five million, four hundred sixty-six thousand, four hundred twenty-one".