Base | Representation |
---|---|
bin | 1110110111001100001110… |
… | …0010101010111110110010 |
3 | 2010212012211211010101201102 |
4 | 3231303003202222332302 |
5 | 4120214024034140200 |
6 | 54431034540204402 |
7 | 3304423355130413 |
oct | 355630342527662 |
9 | 63765754111642 |
10 | 16341336240050 |
11 | 523035a320728 |
12 | 19bb088539702 |
13 | 916c9b182753 |
14 | 406cd3ca380a |
15 | 1d512051e6d5 |
hex | edcc38aafb2 |
16341336240050 has 48 divisors (see below), whose sum is σ = 31103726734080. Its totient is φ = 6384114891840.
The previous prime is 16341336240049. The next prime is 16341336240077. The reversal of 16341336240050 is 5004263314361.
It is a super-2 number, since 2×163413362400502 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16341336239986 and 16341336240013.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 34645196 + ... + 35113704.
It is an arithmetic number, because the mean of its divisors is an integer number (647994306960).
Almost surely, 216341336240050 is an apocalyptic number.
16341336240050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
16341336240050 is a deficient number, since it is larger than the sum of its proper divisors (14762390494030).
16341336240050 is a wasteful number, since it uses less digits than its factorization.
16341336240050 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 484787 (or 484782 counting only the distinct ones).
The product of its (nonzero) digits is 155520, while the sum is 38.
The spelling of 16341336240050 in words is "sixteen trillion, three hundred forty-one billion, three hundred thirty-six million, two hundred forty thousand, fifty".
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