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16355445042133 is a prime number
BaseRepresentation
bin1110111000000000110001…
…1111011110101111010101
32010220120021002022210200201
43232000030133132233111
54120431422412322013
654441330540540501
73305433114021241
oct356001437365725
963816232283621
1016355445042133
11523633a38253a
121a01965551731
13918409197652
144078719bd421
151d5698e953dd
hexee00c7debd5

16355445042133 has 2 divisors, whose sum is σ = 16355445042134. Its totient is φ = 16355445042132.

The previous prime is 16355445041981. The next prime is 16355445042137. The reversal of 16355445042133 is 33124054455361.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15969478569489 + 385966472644 = 3996183^2 + 621262^2 .

It is an emirp because it is prime and its reverse (33124054455361) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16355445042133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16355445042137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8177722521066 + 8177722521067.

It is an arithmetic number, because the mean of its divisors is an integer number (8177722521067).

Almost surely, 216355445042133 is an apocalyptic number.

It is an amenable number.

16355445042133 is a deficient number, since it is larger than the sum of its proper divisors (1).

16355445042133 is an equidigital number, since it uses as much as digits as its factorization.

16355445042133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592000, while the sum is 46.

Adding to 16355445042133 its reverse (33124054455361), we get a palindrome (49479499497494).

The spelling of 16355445042133 in words is "sixteen trillion, three hundred fifty-five billion, four hundred forty-five million, forty-two thousand, one hundred thirty-three".