Base | Representation |
---|---|
bin | 10111110111011110001… |
… | …111010111011111011111 |
3 | 12210210102011101222220001 |
4 | 113313132033113133133 |
5 | 203332421421010421 |
6 | 3253242345035131 |
7 | 226331324262025 |
oct | 27673617273737 |
9 | 5723364358801 |
10 | 1640111110111 |
11 | 582626a67171 |
12 | 225a45a85aa7 |
13 | bb87b00c016 |
14 | 5954b93c715 |
15 | 2c9e2c17691 |
hex | 17dde3d77df |
1640111110111 has 2 divisors, whose sum is σ = 1640111110112. Its totient is φ = 1640111110110.
The previous prime is 1640111110081. The next prime is 1640111110117. The reversal of 1640111110111 is 1110111110461.
It is a strong prime.
It is an emirp because it is prime and its reverse (1110111110461) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1640111110111 - 27 = 1640111109983 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1640111110117) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 820055555055 + 820055555056.
It is an arithmetic number, because the mean of its divisors is an integer number (820055555056).
Almost surely, 21640111110111 is an apocalyptic number.
1640111110111 is a deficient number, since it is larger than the sum of its proper divisors (1).
1640111110111 is an equidigital number, since it uses as much as digits as its factorization.
1640111110111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 19.
Adding to 1640111110111 its reverse (1110111110461), we get a palindrome (2750222220572).
The spelling of 1640111110111 in words is "one trillion, six hundred forty billion, one hundred eleven million, one hundred ten thousand, one hundred eleven".
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