Base | Representation |
---|---|
bin | 1001100011000000001… |
… | …1110101001010000011 |
3 | 120200100111021201112222 |
4 | 2120300003311022003 |
5 | 10141400324132104 |
6 | 203203020041255 |
7 | 14564306034113 |
oct | 2306003651203 |
9 | 520314251488 |
10 | 164015067779 |
11 | 63616258aa2 |
12 | 2795439322b |
13 | 1260b035784 |
14 | 7d1cc6b043 |
15 | 43ee1dc1be |
hex | 26300f5283 |
164015067779 has 2 divisors, whose sum is σ = 164015067780. Its totient is φ = 164015067778.
The previous prime is 164015067773. The next prime is 164015067781. The reversal of 164015067779 is 977760510461.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 164015067779 - 228 = 163746632323 is a prime.
Together with 164015067781, it forms a pair of twin primes.
It is a Chen prime.
It is a self number, because there is not a number n which added to its sum of digits gives 164015067779.
It is not a weakly prime, because it can be changed into another prime (164015067773) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82007533889 + 82007533890.
It is an arithmetic number, because the mean of its divisors is an integer number (82007533890).
Almost surely, 2164015067779 is an apocalyptic number.
164015067779 is a deficient number, since it is larger than the sum of its proper divisors (1).
164015067779 is an equidigital number, since it uses as much as digits as its factorization.
164015067779 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2222640, while the sum is 53.
The spelling of 164015067779 in words is "one hundred sixty-four billion, fifteen million, sixty-seven thousand, seven hundred seventy-nine".
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