164038031 has 2 divisors, whose sum is σ = 164038032. Its totient is φ = 164038030.

The previous prime is 164038013. The next prime is 164038033. The reversal of 164038031 is 130830461.

164038031 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with previous prime (164038013) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (130830461) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 164038031 - 2²² = 159843727 is a prime.

It is a super-2 number, since 2×164038031² = 53816951228713922, which contains 22 as substring.

Together with 164038033, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (164038033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82019015 + 82019016.

It is an arithmetic number, because the mean of its divisors is an integer number (82019016).

Almost surely, 2^164038031 is an apocalyptic number.

164038031 is a deficient number, since it is larger than the sum of its proper divisors (1).

164038031 is an equidigital number, since it uses as much as digits as its factorization.

164038031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 26.

The square root of 164038031 is about 12807.7332498768. The cubic root of 164038031 is about 547.4126752716.

Adding to 164038031 its reverse (130830461), we get a palindrome (294868492).

The spelling of 164038031 in words is "one hundred sixty-four million, thirty-eight thousand, thirty-one".