Base | Representation |
---|---|
bin | 11110100100001111… |
… | …11111101100001101 |
3 | 1120100122201012102121 |
4 | 33102013333230031 |
5 | 232102003310013 |
6 | 11312211452541 |
7 | 1120442336656 |
oct | 172207775415 |
9 | 46318635377 |
10 | 16410213133 |
11 | 6a61157016 |
12 | 321b8b7151 |
13 | 1716a623b2 |
14 | b1963452d |
15 | 660a2558d |
hex | 3d21ffb0d |
16410213133 has 2 divisors, whose sum is σ = 16410213134. Its totient is φ = 16410213132.
The previous prime is 16410213013. The next prime is 16410213199. The reversal of 16410213133 is 33131201461.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 16244267209 + 165945924 = 127453^2 + 12882^2 .
It is a cyclic number.
It is not a de Polignac number, because 16410213133 - 217 = 16410082061 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 16410213098 and 16410213107.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16410213733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8205106566 + 8205106567.
It is an arithmetic number, because the mean of its divisors is an integer number (8205106567).
Almost surely, 216410213133 is an apocalyptic number.
It is an amenable number.
16410213133 is a deficient number, since it is larger than the sum of its proper divisors (1).
16410213133 is an equidigital number, since it uses as much as digits as its factorization.
16410213133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 16410213133 its reverse (33131201461), we get a palindrome (49541414594).
The spelling of 16410213133 in words is "sixteen billion, four hundred ten million, two hundred thirteen thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •