Base | Representation |
---|---|
bin | 1110111011110110101101… |
… | …1111110011001001011011 |
3 | 2011010212200000122110100001 |
4 | 3232331223133303021123 |
5 | 4123022124122030213 |
6 | 54531525520553431 |
7 | 3313261113266665 |
oct | 356755337631133 |
9 | 64125600573301 |
10 | 16421463470683 |
11 | 5261338027a97 |
12 | 1a1270aa82877 |
13 | 9216ca77365b |
14 | 40ab358bb535 |
15 | 1d725ec711dd |
hex | eef6b7f325b |
16421463470683 has 2 divisors, whose sum is σ = 16421463470684. Its totient is φ = 16421463470682.
The previous prime is 16421463470681. The next prime is 16421463470723. The reversal of 16421463470683 is 38607436412461.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16421463470683 - 21 = 16421463470681 is a prime.
Together with 16421463470681, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (16421463470681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8210731735341 + 8210731735342.
It is an arithmetic number, because the mean of its divisors is an integer number (8210731735342).
Almost surely, 216421463470683 is an apocalyptic number.
16421463470683 is a deficient number, since it is larger than the sum of its proper divisors (1).
16421463470683 is an equidigital number, since it uses as much as digits as its factorization.
16421463470683 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13934592, while the sum is 55.
The spelling of 16421463470683 in words is "sixteen trillion, four hundred twenty-one billion, four hundred sixty-three million, four hundred seventy thousand, six hundred eighty-three".
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