Base | Representation |
---|---|
bin | 1110111100100110000011… |
… | …0111110101110000111101 |
3 | 2011012002110120110101200102 |
4 | 3233021200313311300331 |
5 | 4123224140023002443 |
6 | 54541430432410445 |
7 | 3314221025132330 |
oct | 357114067656075 |
9 | 64162416411612 |
10 | 16434170125373 |
11 | 5266768663800 |
12 | 1a150763a6a25 |
13 | 922974137540 |
14 | 40b5bd2c6617 |
15 | 1d775557acb8 |
hex | ef260df5c3d |
16434170125373 has 96 divisors (see below), whose sum is σ = 22372600320000. Its totient is φ = 11746453023360.
The previous prime is 16434170125361. The next prime is 16434170125403. The reversal of 16434170125373 is 37352107143461.
It is not a de Polignac number, because 16434170125373 - 24 = 16434170125357 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (16434170125333) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4696817378 + ... + 4696820876.
It is an arithmetic number, because the mean of its divisors is an integer number (233047920000).
Almost surely, 216434170125373 is an apocalyptic number.
16434170125373 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
16434170125373 is a deficient number, since it is larger than the sum of its proper divisors (5938430194627).
16434170125373 is a wasteful number, since it uses less digits than its factorization.
16434170125373 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6103 (or 6092 counting only the distinct ones).
The product of its (nonzero) digits is 1270080, while the sum is 47.
The spelling of 16434170125373 in words is "sixteen trillion, four hundred thirty-four billion, one hundred seventy million, one hundred twenty-five thousand, three hundred seventy-three".
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