Base | Representation |
---|---|
bin | 1110111101000011101100… |
… | …1011011111111111010111 |
3 | 2011012212000011000000201101 |
4 | 3233100323023133333113 |
5 | 4123341434141220242 |
6 | 54545224214410531 |
7 | 3314622152206411 |
oct | 357207313377727 |
9 | 64185004000641 |
10 | 16442127679447 |
11 | 526a08147a978 |
12 | 1a16717360a47 |
13 | 923641938712 |
14 | 40bb360a19b1 |
15 | 1d7a6de8e9b7 |
hex | ef43b2dffd7 |
16442127679447 has 2 divisors, whose sum is σ = 16442127679448. Its totient is φ = 16442127679446.
The previous prime is 16442127679427. The next prime is 16442127679487. The reversal of 16442127679447 is 74497672124461.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16442127679447 - 219 = 16442127155159 is a prime.
It is a super-3 number, since 3×164421276794473 (a number of 41 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (16442127679427) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221063839723 + 8221063839724.
It is an arithmetic number, because the mean of its divisors is an integer number (8221063839724).
Almost surely, 216442127679447 is an apocalyptic number.
16442127679447 is a deficient number, since it is larger than the sum of its proper divisors (1).
16442127679447 is an equidigital number, since it uses as much as digits as its factorization.
16442127679447 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 113799168, while the sum is 64.
The spelling of 16442127679447 in words is "sixteen trillion, four hundred forty-two billion, one hundred twenty-seven million, six hundred seventy-nine thousand, four hundred forty-seven".
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