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16442145026143 is a prime number
BaseRepresentation
bin1110111101000011110000…
…1101101011000001011111
32011012212001100122022220121
43233100330031223001133
54123342003111314033
654545230034255411
73314622452515024
oct357207415530137
964185040568817
1016442145026143
11526a090248791
121a16721127567
13923645400235
1440bb384d954b
151d7a7076962d
hexef43c36b05f

16442145026143 has 2 divisors, whose sum is σ = 16442145026144. Its totient is φ = 16442145026142.

The previous prime is 16442145026141. The next prime is 16442145026173. The reversal of 16442145026143 is 34162054124461.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 16442145026143 - 21 = 16442145026141 is a prime.

It is a super-3 number, since 3×164421450261433 (a number of 41 digits) contains 333 as substring.

Together with 16442145026141, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 16442145026143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16442145026141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221072513071 + 8221072513072.

It is an arithmetic number, because the mean of its divisors is an integer number (8221072513072).

Almost surely, 216442145026143 is an apocalyptic number.

16442145026143 is a deficient number, since it is larger than the sum of its proper divisors (1).

16442145026143 is an equidigital number, since it uses as much as digits as its factorization.

16442145026143 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 552960, while the sum is 43.

The spelling of 16442145026143 in words is "sixteen trillion, four hundred forty-two billion, one hundred forty-five million, twenty-six thousand, one hundred forty-three".