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16443471107663 is a prime number
BaseRepresentation
bin1110111101001000101101…
…0000010001011001001111
32011012222110202220020202222
43233102023100101121033
54123402212100421123
654550005405005555
73315000354153635
oct357221320213117
964188422806688
1016443471107663
11526a70083a426
121a16a312538bb
139237c706a762
1440bc22689355
151d7aebdac6c8
hexef48b41164f

16443471107663 has 2 divisors, whose sum is σ = 16443471107664. Its totient is φ = 16443471107662.

The previous prime is 16443471107633. The next prime is 16443471107671. The reversal of 16443471107663 is 36670117434461.

16443471107663 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16443471107663 - 220 = 16443470059087 is a prime.

It is a super-3 number, since 3×164434711076633 (a number of 41 digits) contains 333 as substring.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16443471107633) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8221735553831 + 8221735553832.

It is an arithmetic number, because the mean of its divisors is an integer number (8221735553832).

Almost surely, 216443471107663 is an apocalyptic number.

16443471107663 is a deficient number, since it is larger than the sum of its proper divisors (1).

16443471107663 is an equidigital number, since it uses as much as digits as its factorization.

16443471107663 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6096384, while the sum is 53.

The spelling of 16443471107663 in words is "sixteen trillion, four hundred forty-three billion, four hundred seventy-one million, one hundred seven thousand, six hundred sixty-three".