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165413024111 is a prime number
BaseRepresentation
bin1001101000001101100…
…0100111000101101111
3120210221220210021010102
42122003120213011233
510202231213232421
6203553435101315
714644042335416
oct2320330470557
9523856707112
10165413024111
1164173381305
12280845a183b
13127a1849c7a
1480127aa47d
154481ccb60b
hex268362716f

165413024111 has 2 divisors, whose sum is σ = 165413024112. Its totient is φ = 165413024110.

The previous prime is 165413024071. The next prime is 165413024143. The reversal of 165413024111 is 111420314561.

165413024111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 165413024111 - 218 = 165412761967 is a prime.

It is a super-2 number, since 2×1654130241112 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (165413024411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82706512055 + 82706512056.

It is an arithmetic number, because the mean of its divisors is an integer number (82706512056).

Almost surely, 2165413024111 is an apocalyptic number.

165413024111 is a deficient number, since it is larger than the sum of its proper divisors (1).

165413024111 is an equidigital number, since it uses as much as digits as its factorization.

165413024111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 165413024111 its reverse (111420314561), we get a palindrome (276833338672).

The spelling of 165413024111 in words is "one hundred sixty-five billion, four hundred thirteen million, twenty-four thousand, one hundred eleven".