Base | Representation |
---|---|
bin | 1001101000001101100… |
… | …0100111000101110000 |
3 | 120210221220210021010110 |
4 | 2122003120213011300 |
5 | 10202231213232422 |
6 | 203553435101320 |
7 | 14644042335420 |
oct | 2320330470560 |
9 | 523856707113 |
10 | 165413024112 |
11 | 64173381306 |
12 | 280845a1840 |
13 | 127a1849c7b |
14 | 80127aa480 |
15 | 4481ccb60c |
hex | 2683627170 |
165413024112 has 80 divisors (see below), whose sum is σ = 488868250112. Its totient is φ = 47211897600.
The previous prime is 165413024111. The next prime is 165413024143. The reversal of 165413024112 is 211420314561.
165413024112 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1654130241122 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 165413024112.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (165413024111) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 70362 + ... + 579462.
Almost surely, 2165413024112 is an apocalyptic number.
165413024112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 165413024112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (244434125056).
165413024112 is an abundant number, since it is smaller than the sum of its proper divisors (323455226000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
165413024112 is a wasteful number, since it uses less digits than its factorization.
165413024112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 510086 (or 510080 counting only the distinct ones).
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 165413024112 its reverse (211420314561), we get a palindrome (376833338673).
The spelling of 165413024112 in words is "one hundred sixty-five billion, four hundred thirteen million, twenty-four thousand, one hundred twelve".
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