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16564713350183 is a prime number
BaseRepresentation
bin1111000100001100010111…
…0110101110010000100111
32011122120102100120022122122
43301003011312232100213
54132344013104201213
655121420235020155
73326522016212435
oct361030566562047
964576370508578
1016564713350183
115307067932759
121a36428b9a65b
1393207971976b
14413a44999d55
151dad45e44d08
hexf10c5dae427

16564713350183 has 2 divisors, whose sum is σ = 16564713350184. Its totient is φ = 16564713350182.

The previous prime is 16564713350147. The next prime is 16564713350191. The reversal of 16564713350183 is 38105331746561.

16564713350183 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 16564713350183 - 240 = 15465201722407 is a prime.

It is a super-2 number, since 2×165647133501832 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (16564713350083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8282356675091 + 8282356675092.

It is an arithmetic number, because the mean of its divisors is an integer number (8282356675092).

Almost surely, 216564713350183 is an apocalyptic number.

16564713350183 is a deficient number, since it is larger than the sum of its proper divisors (1).

16564713350183 is an equidigital number, since it uses as much as digits as its factorization.

16564713350183 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5443200, while the sum is 53.

The spelling of 16564713350183 in words is "sixteen trillion, five hundred sixty-four billion, seven hundred thirteen million, three hundred fifty thousand, one hundred eighty-three".