Base | Representation |
---|---|
bin | 1001101100011000010… |
… | …1101111001100000111 |
3 | 120220211220121202021021 |
4 | 2123012011233030013 |
5 | 10212024212300043 |
6 | 204300453532011 |
7 | 15013551630241 |
oct | 2330605571407 |
9 | 526756552237 |
10 | 166532150023 |
11 | 6469806a158 |
12 | 28337344007 |
13 | 1291c666255 |
14 | 80bb287091 |
15 | 44ea18e3ed |
hex | 26c616f307 |
166532150023 has 2 divisors, whose sum is σ = 166532150024. Its totient is φ = 166532150022.
The previous prime is 166532149963. The next prime is 166532150047. The reversal of 166532150023 is 320051235661.
166532150023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (320051235661) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-166532150023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (166532150123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 83266075011 + 83266075012.
It is an arithmetic number, because the mean of its divisors is an integer number (83266075012).
Almost surely, 2166532150023 is an apocalyptic number.
166532150023 is a deficient number, since it is larger than the sum of its proper divisors (1).
166532150023 is an equidigital number, since it uses as much as digits as its factorization.
166532150023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 32400, while the sum is 34.
Adding to 166532150023 its reverse (320051235661), we get a palindrome (486583385684).
The spelling of 166532150023 in words is "one hundred sixty-six billion, five hundred thirty-two million, one hundred fifty thousand, twenty-three".
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