Base | Representation |
---|---|
bin | 11000010010111100001… |
… | …010100011011001011011 |
3 | 12220121112120211212221001 |
4 | 120102330022203121123 |
5 | 204323322133201013 |
6 | 3315001112125431 |
7 | 231424230330013 |
oct | 30227412433133 |
9 | 5817476755831 |
10 | 1669604193883 |
11 | 59409104a56a |
12 | 22b6b7096877 |
13 | c159b369c92 |
14 | 5ab48910c43 |
15 | 2d66c0adddd |
hex | 184bc2a365b |
1669604193883 has 2 divisors, whose sum is σ = 1669604193884. Its totient is φ = 1669604193882.
The previous prime is 1669604193877. The next prime is 1669604193947. The reversal of 1669604193883 is 3883914069661.
It is an a-pointer prime, because the next prime (1669604193947) can be obtained adding 1669604193883 to its sum of digits (64).
It is a weak prime.
It is an emirp because it is prime and its reverse (3883914069661) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1669604193883 - 217 = 1669604062811 is a prime.
It is a super-3 number, since 3×16696041938833 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1669604193863) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 834802096941 + 834802096942.
It is an arithmetic number, because the mean of its divisors is an integer number (834802096942).
Almost surely, 21669604193883 is an apocalyptic number.
1669604193883 is a deficient number, since it is larger than the sum of its proper divisors (1).
1669604193883 is an equidigital number, since it uses as much as digits as its factorization.
1669604193883 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40310784, while the sum is 64.
The spelling of 1669604193883 in words is "one trillion, six hundred sixty-nine billion, six hundred four million, one hundred ninety-three thousand, eight hundred eighty-three".
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