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16805047601 is a prime number
BaseRepresentation
bin11111010011010100…
…01010110100110001
31121101011122212111102
433221222022310301
5233404043010401
611415314254145
71133305355606
oct175152126461
947334585442
1016805047601
117144013aa1
12330bb87355
13177a7b5764
14b55c526ad
1568551856b
hex3e9a8ad31

16805047601 has 2 divisors, whose sum is σ = 16805047602. Its totient is φ = 16805047600.

The previous prime is 16805047583. The next prime is 16805047603. The reversal of 16805047601 is 10674050861.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15361123600 + 1443924001 = 123940^2 + 37999^2 .

It is an emirp because it is prime and its reverse (10674050861) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16805047601 is a prime.

Together with 16805047603, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (16805047603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8402523800 + 8402523801.

It is an arithmetic number, because the mean of its divisors is an integer number (8402523801).

Almost surely, 216805047601 is an apocalyptic number.

It is an amenable number.

16805047601 is a deficient number, since it is larger than the sum of its proper divisors (1).

16805047601 is an equidigital number, since it uses as much as digits as its factorization.

16805047601 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 40320, while the sum is 38.

The spelling of 16805047601 in words is "sixteen billion, eight hundred five million, forty-seven thousand, six hundred one".