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168114552701 is a prime number
BaseRepresentation
bin1001110010010001101…
…0000111111101111101
3121001221012012010122212
42130210122013331331
510223244311141301
6205121502150205
715101015056154
oct2344432077575
9531835163585
10168114552701
116532a311767
12286b9282365
1312b1244a3b4
1481cb4ba59b
15458e0644bb
hex2724687f7d

168114552701 has 2 divisors, whose sum is σ = 168114552702. Its totient is φ = 168114552700.

The previous prime is 168114552691. The next prime is 168114552703. The reversal of 168114552701 is 107255411861.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 151086912601 + 17027640100 = 388699^2 + 130490^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-168114552701 is a prime.

Together with 168114552703, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (168114552703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84057276350 + 84057276351.

It is an arithmetic number, because the mean of its divisors is an integer number (84057276351).

Almost surely, 2168114552701 is an apocalyptic number.

It is an amenable number.

168114552701 is a deficient number, since it is larger than the sum of its proper divisors (1).

168114552701 is an equidigital number, since it uses as much as digits as its factorization.

168114552701 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 67200, while the sum is 41.

The spelling of 168114552701 in words is "one hundred sixty-eight billion, one hundred fourteen million, five hundred fifty-two thousand, seven hundred one".