Base | Representation |
---|---|
bin | 11000011111010010100… |
… | …001111010001010111101 |
3 | 12221212202201002221101101 |
4 | 120133102201322022331 |
5 | 210033001231121432 |
6 | 3325032554413101 |
7 | 232403642451304 |
oct | 30372241721275 |
9 | 5855681087341 |
10 | 1682864317117 |
11 | 5997760423a5 |
12 | 232197a31191 |
13 | c29025b7049 |
14 | 5b645a2d43b |
15 | 2db962944e7 |
hex | 187d287a2bd |
1682864317117 has 2 divisors, whose sum is σ = 1682864317118. Its totient is φ = 1682864317116.
The previous prime is 1682864317051. The next prime is 1682864317133. The reversal of 1682864317117 is 7117134682861.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1631326690756 + 51537626361 = 1277234^2 + 227019^2 .
It is a cyclic number.
It is not a de Polignac number, because 1682864317117 - 27 = 1682864316989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1682864317187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 841432158558 + 841432158559.
It is an arithmetic number, because the mean of its divisors is an integer number (841432158559).
Almost surely, 21682864317117 is an apocalyptic number.
It is an amenable number.
1682864317117 is a deficient number, since it is larger than the sum of its proper divisors (1).
1682864317117 is an equidigital number, since it uses as much as digits as its factorization.
1682864317117 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2709504, while the sum is 55.
Adding to 1682864317117 its reverse (7117134682861), we get a palindrome (8799998999978).
The spelling of 1682864317117 in words is "one trillion, six hundred eighty-two billion, eight hundred sixty-four million, three hundred seventeen thousand, one hundred seventeen".
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