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168426426293 is a prime number
BaseRepresentation
bin1001110011011011111…
…1110100111110110101
3121002201221000221210122
42130312333310332311
510224414131120133
6205212442501325
715111523000466
oct2346677647665
9532657027718
10168426426293
116547a365a34
1228785804845
1312b61c44798
14821aaa0d6d
1545ab61b498
hex2736ff4fb5

168426426293 has 2 divisors, whose sum is σ = 168426426294. Its totient is φ = 168426426292.

The previous prime is 168426426251. The next prime is 168426426319. The reversal of 168426426293 is 392624624861.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 165036625009 + 3389801284 = 406247^2 + 58222^2 .

It is a cyclic number.

It is not a de Polignac number, because 168426426293 - 218 = 168426164149 is a prime.

It is a super-3 number, since 3×1684264262933 (a number of 35 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (168426420293) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 84213213146 + 84213213147.

It is an arithmetic number, because the mean of its divisors is an integer number (84213213147).

Almost surely, 2168426426293 is an apocalyptic number.

It is an amenable number.

168426426293 is a deficient number, since it is larger than the sum of its proper divisors (1).

168426426293 is an equidigital number, since it uses as much as digits as its factorization.

168426426293 is an evil number, because the sum of its binary digits is even.

The product of its digits is 5971968, while the sum is 53.

The spelling of 168426426293 in words is "one hundred sixty-eight billion, four hundred twenty-six million, four hundred twenty-six thousand, two hundred ninety-three".